Mathématiques > Enigmes / Solution Enigme n° 17 : "avec des 3 et des 4" Accueil Mathématiques


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Solution proposée par :
DEMARCQ Florian (501)  ,  BAMBA Alexandre (504)  ,  ROCHE Anthony (504)  et  KISSI Dounya (504)  décembre 2009.
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(3 + 3 + 3) : 3 = 3

(3 x 3 + 3) : 3 = 4

3 + 3 - 3 : 3 = 5

3 + 3 + 3 - 3 = 6

3 + 3 + 3 : 3 = 7

3 x 3 - 3 : 3 = 8

3 x 3 + 3 - 3 = 9

3 x 3 + 3 : 3 = 10

3 x 3 + 3 + 3 = 15


(4 + 4 + 4) : 4 = 3

(4 + 4) : 4 + 4 = 6

4 + 4 - 4 : 4 = 7

4 x 4 - 4 - 4 = 8

4 x 4 + 4 + 4 = 24

(4 + 4) x 4 - 4 = 28

4 x 4 + 4 x 4 = 32

(4 + 4 + 4) x 4 = 48



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